125=(201+225x)/(4+x)

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Solution for 125=(201+225x)/(4+x) equation: 


D( x )

x+4 = 0

x+4 = 0

x+4 = 0

x+4 = 0 // - 4

x = -4

x in (-oo:-4) U (-4:+oo)

125 = (225*x+201)/(x+4) // - (225*x+201)/(x+4)

125-((225*x+201)/(x+4)) = 0

(-1*(225*x+201))/(x+4)+125 = 0

(-1*(225*x+201))/(x+4)+(125*(x+4))/(x+4) = 0

125*(x+4)-1*(225*x+201) = 0

299-100*x = 0

(299-100*x)/(x+4) = 0

(299-100*x)/(x+4) = 0 // * x+4

299-100*x = 0

299-100*x = 0 // - 299

-100*x = -299 // : -100

x = -299/(-100)

x = 299/100

x = 299/100

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