125=1/2(10x-2)+3x

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Solution for 125=1/2(10x-2)+3x equation: 



125=1/2(10x-2)+3x

We move all terms to the left:

125-(1/2(10x-2)+3x)=0



Domain of the equation: 2(10x-2)+3x)!=0

x∈R



We multiply all the terms by the denominator


-(1+125*2(10x-2)+3x)=0



We calculate terms in parentheses: -(1+125*2(10x-2)+3x), so:

1+125*2(10x-2)+3x

determiningTheFunctionDomain
125*2(10x-2)+3x+1

We add all the numbers together, and all the variables

3x+125*2(10x-2)+1

Wy multiply elements

3x+250x(1+1

Back to the equation:

-(3x+250x(1+1)



We add all the numbers together, and all the variables

-(3x+250x2=0

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