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125=1/2(10x-2)=3x
We move all terms to the left:
125-(1/2(10x-2))=0
Domain of the equation: 2(10x-2))!=0We multiply all the terms by the denominator
x∈R
-(1+125*2(10x-2))=0
We calculate terms in parentheses: -(1+125*2(10x-2)), so:We add all the numbers together, and all the variables
1+125*2(10x-2)
determiningTheFunctionDomain 125*2(10x-2)+1
Wy multiply elements
250x(1+1
Back to the equation:
-(250x(1+1)
-(250x2=0
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