125x2-5=0

Solution for 125x2-5=0 equation:

125x^2-5=0

a = 125; b = 0; c = -5;
Δ = b2-4ac
Δ = 02-4·125·(-5)
Δ = 2500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2500}=50$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-50}{2*125}=\frac{-50}{250}
=-1/5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+50}{2*125}=\frac{50}{250}
=1/5
$