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125x=25/5x
We move all terms to the left:
125x-(25/5x)=0
Domain of the equation: 5x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
125x-(+25/5x)=0
We get rid of parentheses
125x-25/5x=0
We multiply all the terms by the denominator
125x*5x-25=0
Wy multiply elements
625x^2-25=0
a = 625; b = 0; c = -25;
Δ = b2-4ac
Δ = 02-4·625·(-25)
Δ = 62500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{62500}=250$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-250}{2*625}=\frac{-250}{1250} =-1/5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+250}{2*625}=\frac{250}{1250} =1/5 $
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