126+(3x+8)+(2x+10)+(3x)=540

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Solution for 126+(3x+8)+(2x+10)+(3x)=540 equation: 



126+(3x+8)+(2x+10)+(3x)=540

We move all terms to the left:

126+(3x+8)+(2x+10)+(3x)-(540)=0

We add all the numbers together, and all the variables

3x+(3x+8)+(2x+10)-414=0

We get rid of parentheses

3x+3x+2x+8+10-414=0

We add all the numbers together, and all the variables

8x-396=0

We move all terms containing x to the left, all other terms to the right

8x=396

x=396/8

x=49+1/2

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