126+3y=2(4y+8)+2(4y+3)

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Solution for 126+3y=2(4y+8)+2(4y+3) equation: 



126+3y=2(4y+8)+2(4y+3)

We move all terms to the left:

126+3y-(2(4y+8)+2(4y+3))=0



We calculate terms in parentheses: -(2(4y+8)+2(4y+3)), so:

2(4y+8)+2(4y+3)

We multiply parentheses

8y+8y+16+6

We add all the numbers together, and all the variables

16y+22

Back to the equation:

-(16y+22)



We get rid of parentheses

3y-16y-22+126=0

We add all the numbers together, and all the variables

-13y+104=0

We move all terms containing y to the left, all other terms to the right

-13y=-104

y=-104/-13

y=+8

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