126+4x=(10x+10)x

Solution for 126+4x=(10x+10)x equation:

126+4x=(10x+10)x

We move all terms to the left:

126+4x-((10x+10)x)=0


We calculate terms in parentheses: -((10x+10)x), so:

(10x+10)x

We multiply parentheses

10x^2+10x

Back to the equation:

-(10x^2+10x)


We get rid of parentheses

-10x^2+4x-10x+126=0

We add all the numbers together, and all the variables

-10x^2-6x+126=0

a = -10; b = -6; c = +126;
Δ = b2-4ac
Δ = -62-4·(-10)·126
Δ = 5076
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{5076}=\sqrt{36*141}=\sqrt{36}*\sqrt{141}=6\sqrt{141}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-6\sqrt{141}}{2*-10}=\frac{6-6\sqrt{141}}{-20}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+6\sqrt{141}}{2*-10}=\frac{6+6\sqrt{141}}{-20}
$