126-5a=3(7-2a)

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Solution for 126-5a=3(7-2a) equation: 



126-5a=3(7-2a)

We move all terms to the left:

126-5a-(3(7-2a))=0

We add all the numbers together, and all the variables

-5a-(3(-2a+7))+126=0



We calculate terms in parentheses: -(3(-2a+7)), so:

3(-2a+7)

We multiply parentheses

-6a+21

Back to the equation:

-(-6a+21)



We get rid of parentheses

-5a+6a-21+126=0

We add all the numbers together, and all the variables

a+105=0

We move all terms containing a to the left, all other terms to the right

a=-105

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