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1260=(16+2x)(28+2x)
We move all terms to the left:
1260-((16+2x)(28+2x))=0
We add all the numbers together, and all the variables
-((2x+16)(2x+28))+1260=0
We multiply parentheses ..
-((+4x^2+56x+32x+448))+1260=0
We calculate terms in parentheses: -((+4x^2+56x+32x+448)), so:We get rid of parentheses
(+4x^2+56x+32x+448)
We get rid of parentheses
4x^2+56x+32x+448
We add all the numbers together, and all the variables
4x^2+88x+448
Back to the equation:
-(4x^2+88x+448)
-4x^2-88x-448+1260=0
We add all the numbers together, and all the variables
-4x^2-88x+812=0
a = -4; b = -88; c = +812;
Δ = b2-4ac
Δ = -882-4·(-4)·812
Δ = 20736
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{20736}=144$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-88)-144}{2*-4}=\frac{-56}{-8} =+7 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-88)+144}{2*-4}=\frac{232}{-8} =-29 $
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