126=1x+(2x-39)

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Solution for 126=1x+(2x-39) equation: 



126=1x+(2x-39)

We move all terms to the left:

126-(1x+(2x-39))=0



We calculate terms in parentheses: -(1x+(2x-39)), so:

1x+(2x-39)

We add all the numbers together, and all the variables

x+(2x-39)

We get rid of parentheses

x+2x-39

We add all the numbers together, and all the variables

3x-39

Back to the equation:

-(3x-39)



We get rid of parentheses

-3x+39+126=0

We add all the numbers together, and all the variables

-3x+165=0

We move all terms containing x to the left, all other terms to the right

-3x=-165

x=-165/-3

x=+55

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