126=4x+22

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Solution for 126=4x+22 equation: 



126=4x+22

We move all terms to the left:

126-(4x+22)=0

We get rid of parentheses

-4x-22+126=0

We add all the numbers together, and all the variables

-4x+104=0

We move all terms containing x to the left, all other terms to the right

-4x=-104

x=-104/-4

x=+26

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