126=4x-(2x-8)+12

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Solution for 126=4x-(2x-8)+12 equation: 



126=4x-(2x-8)+12

We move all terms to the left:

126-(4x-(2x-8)+12)=0



We calculate terms in parentheses: -(4x-(2x-8)+12), so:

4x-(2x-8)+12

We get rid of parentheses

4x-2x+8+12

We add all the numbers together, and all the variables

2x+20

Back to the equation:

-(2x+20)



We get rid of parentheses

-2x-20+126=0

We add all the numbers together, and all the variables

-2x+106=0

We move all terms containing x to the left, all other terms to the right

-2x=-106

x=-106/-2

x=+53

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