126=x(2x-4)

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Solution for 126=x(2x-4) equation:



126=x(2x-4)
We move all terms to the left:
126-(x(2x-4))=0
We calculate terms in parentheses: -(x(2x-4)), so:
x(2x-4)
We multiply parentheses
2x^2-4x
Back to the equation:
-(2x^2-4x)
We get rid of parentheses
-2x^2+4x+126=0
a = -2; b = 4; c = +126;
Δ = b2-4ac
Δ = 42-4·(-2)·126
Δ = 1024
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1024}=32$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-32}{2*-2}=\frac{-36}{-4} =+9 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+32}{2*-2}=\frac{28}{-4} =-7 $

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