126x2-504x=0

Solution for 126x2-504x=0 equation:

126x^2-504x=0

a = 126; b = -504; c = 0;
Δ = b2-4ac
Δ = -5042-4·126·0
Δ = 254016
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{254016}=504$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-504)-504}{2*126}=\frac{0}{252}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-504)+504}{2*126}=\frac{1008}{252}
=4
$