127=4+3(5-6b)

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Solution for 127=4+3(5-6b) equation: 



127=4+3(5-6b)

We move all terms to the left:

127-(4+3(5-6b))=0

We add all the numbers together, and all the variables

-(4+3(-6b+5))+127=0



We calculate terms in parentheses: -(4+3(-6b+5)), so:

4+3(-6b+5)

determiningTheFunctionDomain
3(-6b+5)+4

We multiply parentheses

-18b+15+4

We add all the numbers together, and all the variables

-18b+19

Back to the equation:

-(-18b+19)



We get rid of parentheses

18b-19+127=0

We add all the numbers together, and all the variables

18b+108=0

We move all terms containing b to the left, all other terms to the right

18b=-108

b=-108/18

b=-6

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