127=4a-5(-7a-2)

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Solution for 127=4a-5(-7a-2) equation: 



127=4a-5(-7a-2)

We move all terms to the left:

127-(4a-5(-7a-2))=0



We calculate terms in parentheses: -(4a-5(-7a-2)), so:

4a-5(-7a-2)

We multiply parentheses

4a+35a+10

We add all the numbers together, and all the variables

39a+10

Back to the equation:

-(39a+10)



We get rid of parentheses

-39a-10+127=0

We add all the numbers together, and all the variables

-39a+117=0

We move all terms containing a to the left, all other terms to the right

-39a=-117

a=-117/-39

a=+3

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