127=5a-4(-10a+2)

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Solution for 127=5a-4(-10a+2) equation:



127=5a-4(-10a+2)
We move all terms to the left:
127-(5a-4(-10a+2))=0
We calculate terms in parentheses: -(5a-4(-10a+2)), so:
5a-4(-10a+2)
We multiply parentheses
5a+40a-8
We add all the numbers together, and all the variables
45a-8
Back to the equation:
-(45a-8)
We get rid of parentheses
-45a+8+127=0
We add all the numbers together, and all the variables
-45a+135=0
We move all terms containing a to the left, all other terms to the right
-45a=-135
a=-135/-45
a=+3

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