127=5b+6(b-1)

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Solution for 127=5b+6(b-1) equation: 



127=5b+6(b-1)

We move all terms to the left:

127-(5b+6(b-1))=0



We calculate terms in parentheses: -(5b+6(b-1)), so:

5b+6(b-1)

We multiply parentheses

5b+6b-6

We add all the numbers together, and all the variables

11b-6

Back to the equation:

-(11b-6)



We get rid of parentheses

-11b+6+127=0

We add all the numbers together, and all the variables

-11b+133=0

We move all terms containing b to the left, all other terms to the right

-11b=-133

b=-133/-11

b=12+1/11

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