127=7-10(q-6)

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Solution for 127=7-10(q-6) equation: 



127=7-10(q-6)

We move all terms to the left:

127-(7-10(q-6))=0



We calculate terms in parentheses: -(7-10(q-6)), so:

7-10(q-6)

determiningTheFunctionDomain
-10(q-6)+7

We multiply parentheses

-10q+60+7

We add all the numbers together, and all the variables

-10q+67

Back to the equation:

-(-10q+67)



We get rid of parentheses

10q-67+127=0

We add all the numbers together, and all the variables

10q+60=0

We move all terms containing q to the left, all other terms to the right

10q=-60

q=-60/10

q=-6

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