127=8(1+2b)+b

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Solution for 127=8(1+2b)+b equation: 



127=8(1+2b)+b

We move all terms to the left:

127-(8(1+2b)+b)=0

We add all the numbers together, and all the variables

-(8(2b+1)+b)+127=0



We calculate terms in parentheses: -(8(2b+1)+b), so:

8(2b+1)+b

We add all the numbers together, and all the variables

b+8(2b+1)

We multiply parentheses

b+16b+8

We add all the numbers together, and all the variables

17b+8

Back to the equation:

-(17b+8)



We get rid of parentheses

-17b-8+127=0

We add all the numbers together, and all the variables

-17b+119=0

We move all terms containing b to the left, all other terms to the right

-17b=-119

b=-119/-17

b=+7

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