128+3y=4y-4

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Solution for 128+3y=4y-4 equation: 



128+3y=4y-4

We move all terms to the left:

128+3y-(4y-4)=0

We get rid of parentheses

3y-4y+4+128=0

We add all the numbers together, and all the variables

-1y+132=0

We move all terms containing y to the left, all other terms to the right

-y=-132

y=-132/-1

y=+132

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