128+6(x+2)-(128+6x)=12

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Solution for 128+6(x+2)-(128+6x)=12 equation: 



128+6(x+2)-(128+6x)=12

We move all terms to the left:

128+6(x+2)-(128+6x)-(12)=0

We add all the numbers together, and all the variables

6(x+2)-(6x+128)+128-12=0

We add all the numbers together, and all the variables

6(x+2)-(6x+128)+116=0

We multiply parentheses

6x-(6x+128)+12+116=0

We get rid of parentheses

6x-6x-128+12+116=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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