128-(9x-2)=40

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Solution for 128-(9x-2)=40 equation: 



128-(9x-2)=40

We move all terms to the left:

128-(9x-2)-(40)=0

We add all the numbers together, and all the variables

-(9x-2)+88=0

We get rid of parentheses

-9x+2+88=0

We add all the numbers together, and all the variables

-9x+90=0

We move all terms containing x to the left, all other terms to the right

-9x=-90

x=-90/-9

x=+10

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