128=(2x-4)(2x+4)

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Solution for 128=(2x-4)(2x+4) equation: 


Simplifying
128 = (2x + -4)(2x + 4)

Reorder the terms:
128 = (-4 + 2x)(2x + 4)

Reorder the terms:
128 = (-4 + 2x)(4 + 2x)

Multiply (-4 + 2x) * (4 + 2x)
128 = (-4(4 + 2x) + 2x * (4 + 2x))
128 = ((4 * -4 + 2x * -4) + 2x * (4 + 2x))
128 = ((-16 + -8x) + 2x * (4 + 2x))
128 = (-16 + -8x + (4 * 2x + 2x * 2x))
128 = (-16 + -8x + (8x + 4x2))

Combine like terms: -8x + 8x = 0
128 = (-16 + 0 + 4x2)
128 = (-16 + 4x2)

Solving
128 = -16 + 4x2

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-4x2' to each side of the equation.
128 + -4x2 = -16 + 4x2 + -4x2

Combine like terms: 4x2 + -4x2 = 0
128 + -4x2 = -16 + 0
128 + -4x2 = -16

Add '-128' to each side of the equation.
128 + -128 + -4x2 = -16 + -128

Combine like terms: 128 + -128 = 0
0 + -4x2 = -16 + -128
-4x2 = -16 + -128

Combine like terms: -16 + -128 = -144
-4x2 = -144

Divide each side by '-4'.
x2 = 36

Simplifying
x2 = 36

Take the square root of each side:
x = {-6, 6}

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