128=-3x+5(-2+10)

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Solution for 128=-3x+5(-2+10) equation: 



128=-3x+5(-2+10)

We move all terms to the left:

128-(-3x+5(-2+10))=0

We add all the numbers together, and all the variables

-(-3x+58)+128=0

We get rid of parentheses

3x-58+128=0

We add all the numbers together, and all the variables

3x+70=0

We move all terms containing x to the left, all other terms to the right

3x=-70

x=-70/3

x=-23+1/3

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