128=-8(m-2)-6m

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Solution for 128=-8(m-2)-6m equation: 



128=-8(m-2)-6m

We move all terms to the left:

128-(-8(m-2)-6m)=0



We calculate terms in parentheses: -(-8(m-2)-6m), so:

-8(m-2)-6m

We add all the numbers together, and all the variables

-6m-8(m-2)

We multiply parentheses

-6m-8m+16

We add all the numbers together, and all the variables

-14m+16

Back to the equation:

-(-14m+16)



We get rid of parentheses

14m-16+128=0

We add all the numbers together, and all the variables

14m+112=0

We move all terms containing m to the left, all other terms to the right

14m=-112

m=-112/14

m=-8

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