128=2(7k+8)

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Solution for 128=2(7k+8) equation: 



128=2(7k+8)

We move all terms to the left:

128-(2(7k+8))=0



We calculate terms in parentheses: -(2(7k+8)), so:

2(7k+8)

We multiply parentheses

14k+16

Back to the equation:

-(14k+16)



We get rid of parentheses

-14k-16+128=0

We add all the numbers together, and all the variables

-14k+112=0

We move all terms containing k to the left, all other terms to the right

-14k=-112

k=-112/-14

k=+8

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