128=2v+5(4+5v)

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Solution for 128=2v+5(4+5v) equation:


128=2v+5(4+5v)

We simplify the equation to the form, which is simple to understand 
128=2v+5(4+5v)

Reorder the terms in parentheses
128=2v+(+20+25v)

Remove unnecessary parentheses
+128=+2v+20+25v

We move all terms containing v to the left and all other terms to the right. 
-2v-25v=+20-128

We simplify left and right side of the equation. 
-27v=-108

We divide both sides of the equation by -27 to get v. 
v=4

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