128=4(3x+5)

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Solution for 128=4(3x+5) equation: 



128=4(3x+5)

We move all terms to the left:

128-(4(3x+5))=0



We calculate terms in parentheses: -(4(3x+5)), so:

4(3x+5)

We multiply parentheses

12x+20

Back to the equation:

-(12x+20)



We get rid of parentheses

-12x-20+128=0

We add all the numbers together, and all the variables

-12x+108=0

We move all terms containing x to the left, all other terms to the right

-12x=-108

x=-108/-12

x=+9

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