128=4(8+3x)

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Solution for 128=4(8+3x) equation: 



128=4(8+3x)

We move all terms to the left:

128-(4(8+3x))=0

We add all the numbers together, and all the variables

-(4(3x+8))+128=0



We calculate terms in parentheses: -(4(3x+8)), so:

4(3x+8)

We multiply parentheses

12x+32

Back to the equation:

-(12x+32)



We get rid of parentheses

-12x-32+128=0

We add all the numbers together, and all the variables

-12x+96=0

We move all terms containing x to the left, all other terms to the right

-12x=-96

x=-96/-12

x=+8

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