128=4*7*4+2*4h=

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Solution for 128=4*7*4+2*4h= equation: 



128=4*7*4+2*4h=

We move all terms to the left:

128-(4*7*4+2*4h)=0

We add all the numbers together, and all the variables

-(2*4h+112)+128=0

We get rid of parentheses

-2*4h-112+128=0

We add all the numbers together, and all the variables

-2*4h+16=0

Wy multiply elements

-8h+16=0

We move all terms containing h to the left, all other terms to the right

-8h=-16

h=-16/-8

h=+2

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