128=4x-2(7x-4)

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Solution for 128=4x-2(7x-4) equation: 



128=4x-2(7x-4)

We move all terms to the left:

128-(4x-2(7x-4))=0



We calculate terms in parentheses: -(4x-2(7x-4)), so:

4x-2(7x-4)

We multiply parentheses

4x-14x+8

We add all the numbers together, and all the variables

-10x+8

Back to the equation:

-(-10x+8)



We get rid of parentheses

10x-8+128=0

We add all the numbers together, and all the variables

10x+120=0

We move all terms containing x to the left, all other terms to the right

10x=-120

x=-120/10

x=-12

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