128=5(4b-1)-7

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Solution for 128=5(4b-1)-7 equation: 



128=5(4b-1)-7

We move all terms to the left:

128-(5(4b-1)-7)=0



We calculate terms in parentheses: -(5(4b-1)-7), so:

5(4b-1)-7

We multiply parentheses

20b-5-7

We add all the numbers together, and all the variables

20b-12

Back to the equation:

-(20b-12)



We get rid of parentheses

-20b+12+128=0

We add all the numbers together, and all the variables

-20b+140=0

We move all terms containing b to the left, all other terms to the right

-20b=-140

b=-140/-20

b=+7

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