128=7(-4-3v)-5v

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Solution for 128=7(-4-3v)-5v equation: 



128=7(-4-3v)-5v

We move all terms to the left:

128-(7(-4-3v)-5v)=0

We add all the numbers together, and all the variables

-(7(-3v-4)-5v)+128=0



We calculate terms in parentheses: -(7(-3v-4)-5v), so:

7(-3v-4)-5v

We add all the numbers together, and all the variables

-5v+7(-3v-4)

We multiply parentheses

-5v-21v-28

We add all the numbers together, and all the variables

-26v-28

Back to the equation:

-(-26v-28)



We get rid of parentheses

26v+28+128=0

We add all the numbers together, and all the variables

26v+156=0

We move all terms containing v to the left, all other terms to the right

26v=-156

v=-156/26

v=-6

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