128=7x+3(2x+8)

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Solution for 128=7x+3(2x+8) equation: 



128=7x+3(2x+8)

We move all terms to the left:

128-(7x+3(2x+8))=0



We calculate terms in parentheses: -(7x+3(2x+8)), so:

7x+3(2x+8)

We multiply parentheses

7x+6x+24

We add all the numbers together, and all the variables

13x+24

Back to the equation:

-(13x+24)



We get rid of parentheses

-13x-24+128=0

We add all the numbers together, and all the variables

-13x+104=0

We move all terms containing x to the left, all other terms to the right

-13x=-104

x=-104/-13

x=+8

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