128=8(-3r+3)-2r

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Solution for 128=8(-3r+3)-2r equation: 



128=8(-3r+3)-2r

We move all terms to the left:

128-(8(-3r+3)-2r)=0



We calculate terms in parentheses: -(8(-3r+3)-2r), so:

8(-3r+3)-2r

We add all the numbers together, and all the variables

-2r+8(-3r+3)

We multiply parentheses

-2r-24r+24

We add all the numbers together, and all the variables

-26r+24

Back to the equation:

-(-26r+24)



We get rid of parentheses

26r-24+128=0

We add all the numbers together, and all the variables

26r+104=0

We move all terms containing r to the left, all other terms to the right

26r=-104

r=-104/26

r=-4

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