128=80+(4x)

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Solution for 128=80+(4x) equation: 



128=80+(4x)

We move all terms to the left:

128-(80+(4x))=0

We add all the numbers together, and all the variables

-(4x+80)+128=0

We get rid of parentheses

-4x-80+128=0

We add all the numbers together, and all the variables

-4x+48=0

We move all terms containing x to the left, all other terms to the right

-4x=-48

x=-48/-4

x=+12

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