12=(1/5-z)15

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Solution for 12=(1/5-z)15 equation: 



12=(1/5-z)15

We move all terms to the left:

12-((1/5-z)15)=0



Domain of the equation: 5-z)15)!=0

We move all terms containing z to the left, all other terms to the right

-z)15)!=-5

z!=-5/1

z!=-5

z∈R



We add all the numbers together, and all the variables

-((-1z+1/5)15)+12=0

We multiply all the terms by the denominator


-((-1z+1+12*5)15)=0



We calculate terms in parentheses: -((-1z+1+12*5)15), so:

(-1z+1+12*5)15

We add all the numbers together, and all the variables

(-1z+61)15

We multiply parentheses

-15z+915

Back to the equation:

-(-15z+915)



We get rid of parentheses

15z-915=0

We move all terms containing z to the left, all other terms to the right

15z=915

z=915/15

z=61

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