12=(12)+(v-8)/2

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Solution for 12=(12)+(v-8)/2 equation: 



12=(12)+(v-8)/2

We move all terms to the left:

12-((12)+(v-8)/2)=0

We multiply all the terms by the denominator


-(12+(v-8)+12*2)=0



We calculate terms in parentheses: -(12+(v-8)+12*2), so:

12+(v-8)+12*2

determiningTheFunctionDomain
(v-8)+12+12*2

We add all the numbers together, and all the variables

(v-8)+36

We get rid of parentheses

v-8+36

We add all the numbers together, and all the variables

v+28

Back to the equation:

-(v+28)



We get rid of parentheses

-v-28=0

We add all the numbers together, and all the variables

-1v-28=0

We move all terms containing v to the left, all other terms to the right

-v=28

v=28/-1

v=-28

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