12=(2+z)/(-6)

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Solution for 12=(2+z)/(-6) equation: 



12=(2+z)/(-6)

We move all terms to the left:

12-((2+z)/(-6))=0

We add all the numbers together, and all the variables

-((z+2)/(-6))+12=0

We multiply all the terms by the denominator


-((z+2)+12*(-6))=0



We calculate terms in parentheses: -((z+2)+12*(-6)), so:

(z+2)+12*(-6)

We add all the numbers together, and all the variables

(z+2)-72

We get rid of parentheses

z+2-72

We add all the numbers together, and all the variables

z-70

Back to the equation:

-(z-70)



We get rid of parentheses

-z+70=0

We add all the numbers together, and all the variables

-1z+70=0

We move all terms containing z to the left, all other terms to the right

-z=-70

z=-70/-1

z=+70

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