12=(2/5)(9x+25)

Solution for 12=(2/5)(9x+25) equation:

12=(2/5)(9x+25)

We move all terms to the left:

12-((2/5)(9x+25))=0


Domain of the equation: 5)(9x+25))!=0

x∈R


We add all the numbers together, and all the variables

-((+2/5)(9x+25))+12=0

We multiply parentheses ..

-((+18x^2+2/5*25))+12=0

We multiply all the terms by the denominator


-((+18x^2+2+12*5*25))=0


We calculate terms in parentheses: -((+18x^2+2+12*5*25)), so:

(+18x^2+2+12*5*25)

We get rid of parentheses

18x^2+2+12*5*25

We add all the numbers together, and all the variables

18x^2+1502

Back to the equation:

-(18x^2+1502)


We get rid of parentheses

-18x^2-1502=0

a = -18; b = 0; c = -1502;
Δ = b2-4ac
Δ = 02-4·(-18)·(-1502)
Δ = -108144
Delta is less than zero, so there is no solution for the equation