12=(20+4y)/8

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Solution for 12=(20+4y)/8 equation:



12=(20+4y)/8
We move all terms to the left:
12-((20+4y)/8)=0
We add all the numbers together, and all the variables
-((4y+20)/8)+12=0
We multiply all the terms by the denominator
-((4y+20)+12*8)=0
We calculate terms in parentheses: -((4y+20)+12*8), so:
(4y+20)+12*8
We add all the numbers together, and all the variables
(4y+20)+96
We get rid of parentheses
4y+20+96
We add all the numbers together, and all the variables
4y+116
Back to the equation:
-(4y+116)
We get rid of parentheses
-4y-116=0
We move all terms containing y to the left, all other terms to the right
-4y=116
y=116/-4
y=-29

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