12=(20-4y)/3

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Solution for 12=(20-4y)/3 equation: 



12=(20-4y)/3

We move all terms to the left:

12-((20-4y)/3)=0

We add all the numbers together, and all the variables

-((-4y+20)/3)+12=0

We multiply all the terms by the denominator


-((-4y+20)+12*3)=0



We calculate terms in parentheses: -((-4y+20)+12*3), so:

(-4y+20)+12*3

We add all the numbers together, and all the variables

(-4y+20)+36

We get rid of parentheses

-4y+20+36

We add all the numbers together, and all the variables

-4y+56

Back to the equation:

-(-4y+56)



We get rid of parentheses

4y-56=0

We move all terms containing y to the left, all other terms to the right

4y=56

y=56/4

y=14

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