12=(2x-3)/(x+4)

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Solution for 12=(2x-3)/(x+4) equation: 



12=(2x-3)/(x+4)

We move all terms to the left:

12-((2x-3)/(x+4))=0



Domain of the equation: (x+4))!=0

x∈R



We multiply all the terms by the denominator


-((2x-3)+12*(x+4))=0



We calculate terms in parentheses: -((2x-3)+12*(x+4)), so:

(2x-3)+12*(x+4)

We multiply parentheses

(2x-3)+12x+48

We get rid of parentheses

2x+12x-3+48

We add all the numbers together, and all the variables

14x+45

Back to the equation:

-(14x+45)



We get rid of parentheses

-14x-45=0

We move all terms containing x to the left, all other terms to the right

-14x=45

x=45/-14

x=-3+3/14

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