12=(2x-3)/(x+4)

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Solution for 12=(2x-3)/(x+4) equation:



12=(2x-3)/(x+4)
We move all terms to the left:
12-((2x-3)/(x+4))=0
Domain of the equation: (x+4))!=0
x∈R
We multiply all the terms by the denominator
-((2x-3)+12*(x+4))=0
We calculate terms in parentheses: -((2x-3)+12*(x+4)), so:
(2x-3)+12*(x+4)
We multiply parentheses
(2x-3)+12x+48
We get rid of parentheses
2x+12x-3+48
We add all the numbers together, and all the variables
14x+45
Back to the equation:
-(14x+45)
We get rid of parentheses
-14x-45=0
We move all terms containing x to the left, all other terms to the right
-14x=45
x=45/-14
x=-3+3/14

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