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12=(3.14)r2
We move all terms to the left:
12-((3.14)r2)=0
We calculate terms in parentheses: -((3.14)r2), so:We get rid of parentheses
(3.14)r2
We multiply parentheses
3.14r^2
Back to the equation:
-(3.14r^2)
-3.14r^2+12=0
a = -3.14; b = 0; c = +12;
Δ = b2-4ac
Δ = 02-4·(-3.14)·12
Δ = 150.72
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{150.72}}{2*-3.14}=\frac{0-\sqrt{150.72}}{-6.28} =-\frac{\sqrt{}}{-6.28} $$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{150.72}}{2*-3.14}=\frac{0+\sqrt{150.72}}{-6.28} =\frac{\sqrt{}}{-6.28} $
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