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12=(4/3)b
We move all terms to the left:
12-((4/3)b)=0
Domain of the equation: 3)b)!=0We add all the numbers together, and all the variables
b!=0/1
b!=0
b∈R
-((+4/3)b)+12=0
We multiply all the terms by the denominator
-((+4+12*3)b)=0
We calculate terms in parentheses: -((+4+12*3)b), so:b=0/-40
(+4+12*3)b
We add all the numbers together, and all the variables
40b
Back to the equation:
-(40b)
b=0
Równanie nie ma rozwiązania
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