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12=(45x)2
We move all terms to the left:
12-((45x)2)=0
determiningTheFunctionDomain -45x2+12=0
We add all the numbers together, and all the variables
-45x^2+12=0
a = -45; b = 0; c = +12;
Δ = b2-4ac
Δ = 02-4·(-45)·12
Δ = 2160
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{2160}=\sqrt{144*15}=\sqrt{144}*\sqrt{15}=12\sqrt{15}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-12\sqrt{15}}{2*-45}=\frac{0-12\sqrt{15}}{-90} =-\frac{12\sqrt{15}}{-90} =-\frac{2\sqrt{15}}{-15} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+12\sqrt{15}}{2*-45}=\frac{0+12\sqrt{15}}{-90} =\frac{12\sqrt{15}}{-90} =\frac{2\sqrt{15}}{-15} $
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