12=(5/9)(f-32)

Solution for 12=(5/9)(f-32) equation:

12=(5/9)(f-32)

We move all terms to the left:

12-((5/9)(f-32))=0


Domain of the equation: 9)(f-32))!=0

f∈R


We add all the numbers together, and all the variables

-((+5/9)(f-32))+12=0

We multiply parentheses ..

-((+5f^2+5/9*-32))+12=0

We multiply all the terms by the denominator


-((+5f^2+5+12*9*-32))=0


We calculate terms in parentheses: -((+5f^2+5+12*9*-32)), so:

(+5f^2+5+12*9*-32)

We get rid of parentheses

5f^2+5-32+12*9*

We add all the numbers together, and all the variables

5f^2

Back to the equation:

-(5f^2)


a = -5; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-5)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$f=\frac{-b}{2a}=\frac{0}{-10}=0$