12=(7/2)(5x+2)

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Solution for 12=(7/2)(5x+2) equation: 



12=(7/2)(5x+2)

We move all terms to the left:

12-((7/2)(5x+2))=0



Domain of the equation: 2)(5x+2))!=0

x∈R



We add all the numbers together, and all the variables

-((+7/2)(5x+2))+12=0

We multiply parentheses ..

-((+35x^2+7/2*2))+12=0

We multiply all the terms by the denominator


-((+35x^2+7+12*2*2))=0



We calculate terms in parentheses: -((+35x^2+7+12*2*2)), so:

(+35x^2+7+12*2*2)

We get rid of parentheses

35x^2+7+12*2*2

We add all the numbers together, and all the variables

35x^2+55

Back to the equation:

-(35x^2+55)



We get rid of parentheses

-35x^2-55=0

a = -35; b = 0; c = -55;
Δ = b2-4ac
Δ = 02-4·(-35)·(-55)
Δ = -7700
Delta is less than zero, so there is no solution for the equation

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